//螺旋输出1-25
public class Sequence {

public static void main(String[] args) {

int n = 5;
// 0:向右,1:向下,2:向左,3：向上
int direction = 0;
// 行，列
int row = 0, col = 0;
int num = 0;

int[] array = new int[n * n];
while (array[row * n + col] == 0) {

num++;
array[row * n + col] = num;
switch (direction) {

case 0:
col++;
break;
case 1:
row++;
break;
case 2:
col--;
break;
case 3:
row--;
break;
}
if (row == n || col == n || row == -1 || col == -1
|| array[row * n + col] != 0) {

direction++;
if (direction == 4)
direction = 0;
switch (direction) {

case 0:
row++;
col++;
break;
case 1:
row++;
col--;
break;
case 2:
row--;
col--;
break;
case 3:
row--;
col++;
break;
}
}
}

for (int i = 0; i < n; i++) {

for (int j = 0; j < n; j++) {

System.out.printf("%-3s", array[i * n + j]);
}
System.out.println();
}
}

}

-----------------------------------------------------------

//矩阵转换

public class TestArray { public static void main(String[] args) { int array[][] = { { 22, 18, 36 }, { 27, 34, 58 }, { 12, 51, 32 },{ 14, 52, 64 } }; // 创建一个4行3列的二维数组int brray[][] = new int[3][4]; // 创建一个3行4列的数组，用于接收转置后的矩阵System.out.println("原型矩阵例如以下：");for (int i = 0; i < array.length; i++) { // 遍历array数组中的元素for (int j = 0; j < array[i].length; j++) { System.out.print(array[i][j] + " ");}System.out.println();}for (int i = 0; i < array.length; i++) { // 此时的i是array数组的行。brray的列for (int j = 0; j < brray.length; j++) { // 此时的j是array数组的列，brray的行brray[j][i] = array[i][j]; // 将array数组中的第i行j列的元素赋给brray数组中的j行i列}}System.out.println("\n转置后的矩阵例如以下:");for (int i = 0; i < brray.length; i++) { // 遍历转置后brray数组中的元素for (int j = 0; j < brray[i].length; j++) { System.out.print(brray[i][j] + " ");}System.out.println();}} }

本文转自mfrbuaa博客园博客，原文链接：http://www.cnblogs.com/mfrbuaa/p/5193784.html，如需转载请自行联系原作者